Timeline for Battery Life Estimation - Sanity check
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 24, 2018 at 12:32 | vote | accept | Calculon | ||
| Aug 24, 2018 at 12:30 | comment | added | Calculon | I made a mistake when calculating periods. 0.012 is fine but then I did 100-0.012 instead 1-0.012. Thanks everyone! | |
| Aug 24, 2018 at 7:33 | comment | added | jonk | @mkeith Just total Coulombs divided by total time. Pretty much can't go wrong that way. | |
| Aug 24, 2018 at 6:11 | answer | added | Transistor | timeline score: 5 | |
| Aug 24, 2018 at 5:53 | comment | added | user57037 | As far as what did you actually do wrong, it looks like the main problem is that you didn't deal with the percentages correctly. 7/607 = 0.0115. So that is OK. But 600/607 = 0.988. So the full equation is 0.0115 * 5 + 0.988 * 0.07 = 0.127 mA. So your method is OK. You just made some calculation errors. | |
| Aug 24, 2018 at 5:37 | answer | added | Neil_UK | timeline score: 2 | |
| Aug 24, 2018 at 5:21 | comment | added | user57037 | Very nice, Jonk! Much simpler way to see it and calculate it than what I usually do. And as long as the time units are consistent, you could use seconds, or us or ms or whatever (must be same on top and bottom). | |
| Aug 24, 2018 at 5:09 | comment | added | jonk | It is probably easiest to just calculate \$\frac{7\:\text{s}\cdot 5\:\text{mA}+600\:\text{s}\cdot 70\:\mu\text{A}}{607 \:\text{s}}\approx 127\:\mu\text{A}\$. | |
| Aug 24, 2018 at 4:59 | comment | added | user57037 | You definitely made some kind of mistake. There is no combination of 5mA and 70uA that can give you an average of 7mA... | |
| Aug 24, 2018 at 4:54 | history | asked | Calculon | CC BY-SA 4.0 |