Timeline for Calculating necessary transistor for LED switching
Current License: CC BY-SA 4.0
6 events
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| Nov 19, 2018 at 12:41 | history | edited | Electron | CC BY-SA 4.0 |
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| Nov 19, 2018 at 12:19 | comment | added | Vladimir Cravero | The issue is that all fwd voltage of the LEDs are slightly different, and since the current dependency is exponential, you end up with the led with the lowest fwd voltage carrying most of the current. Its life is shortened, then it goes pop, and if it fails open the other LEDs will shortly (seconds) follow. | |
| Nov 19, 2018 at 12:05 | comment | added | Electron | Can you please explain in detail, what will be the problems of using One series resistor for few no of leds... | |
| Nov 19, 2018 at 11:56 | comment | added | Marcus Müller | This neglects information on how to choose which transistor to use, the influence of the Collector-Emitter diode forward voltage on the series resistor, and it shows the bad practice of having one series resistor for multiple LEDs, so: no. | |
| Nov 19, 2018 at 11:54 | history | edited | Electron | CC BY-SA 4.0 |
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| Nov 19, 2018 at 11:46 | history | answered | Electron | CC BY-SA 4.0 |