Timeline for What is the SI unit of magnetic force?
Current License: CC BY-SA 4.0
18 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 22, 2018 at 21:27 | comment | added | The Photon | Let us continue this discussion in chat. | |
| Dec 22, 2018 at 21:00 | comment | added | The Photon | Yes, force is a vector. | |
| Dec 22, 2018 at 20:56 | comment | added | Vyun | But, doesn't a vector shows also the direction, thus, doesn't it mean the force is applied upward or downward on the charge? The reason why I am not asking this on physics or math is because I do not know why two variables horizontal (Bxv) would create a force perpendicular to these. | |
| Dec 22, 2018 at 17:01 | comment | added | The Photon | "Why is a cross product gives another vector which is perpendicular to the parallelogram?" --- This is simply how the cross product is defined. This is a question for mathematics.stackexchange.com, not electronics or even physics. | |
| Dec 22, 2018 at 16:59 | comment | added | The Photon | "What does force being up or down affect on the electric charges' movements?" --- If you apply a downward force on an object it will accelerate downwards. If you apply an upward force on an object, it will accelerate upwards. This is simple mechanics. If you want to ask about this, you should ask on physics.stackexchange.com, not electronics. | |
| Dec 22, 2018 at 16:59 | comment | added | Vyun | No, I am asking about the force. | |
| Dec 22, 2018 at 16:57 | comment | added | The Photon | If you want to know about the units for measuring the magnetic field, that's not a force, it's a magnetic field. If you want to know about the units for that, you should ask a separate question. | |
| Dec 22, 2018 at 16:55 | comment | added | The Photon | @Vyun, the SI unit of force is the newton. It doesn't matter if the force is produced by magentism, static electricity, gravity, or a steam engine. You're free to measure it in dynes or pounds if you like, but that will just force anybody you talk to to have to convert to newtons to compare your numbers with somebody else's. | |
| Dec 22, 2018 at 12:52 | comment | added | Vyun | Why is a cross product gives another vector which is perpendicular to the parallelogram? How can the direction of magnetic force (field and velocity as well) be determined, so that this equation/solution arises? What does force being up or down affect on the electric charges' movements? And I still couldn'T grasph why the force is in Newton. (how to differentiate magnetic flux from magnetic field?) | |
| Dec 22, 2018 at 3:04 | comment | added | analogsystemsrf | @ Vyun If I recall rightly, the Magnetic Field is orthogonal to the Magnetic Force, just because that makes the math work out. DId I phrase that rightly, @ Photon??? | |
| Dec 21, 2018 at 23:28 | comment | added | The Photon | For example, if two parallel wires carry current in the same direction, the force on wire 2 is directly toward wire 1. Measuring this force is actually how the ampere is defined (although this is changing in May 2019). | |
| Dec 21, 2018 at 23:24 | comment | added | The Photon | The cross product lets us calculate both magnitude and direction of the force. The force caused by the B field is not in the same direction as the B vector. | |
| Dec 21, 2018 at 22:52 | comment | added | Vyun | I think I kind of understood. So, it is not something that we conclude logically, but it is because how it (magnitude) can be represented/calculated accurately mathematicaly? I thought the princible was the same as with electrical flux, where E and F are in the same direction, and to find electric field / given area, we multiply E.A.cos (to find the parallel lines and multiply them). I think I need to go over scalar and vectoral multiplications, and I just don't want to memorize, but understand the logic behind it. | |
| Dec 21, 2018 at 21:19 | comment | added | The Photon | Because we find that this math accurately predicts the forces acting on moving particles subject to magnetic effects. (Note: The field itself is also just a mathematical convenience. The way we define the B field produced by a current or magnetic dipole is also part of "the math" that we need to define to make our predictive model) | |
| Dec 21, 2018 at 21:11 | comment | added | Vyun | I don't understand the reason behind that. | |
| Dec 21, 2018 at 21:04 | comment | added | The Photon | The formula you gave is for the magnitude of the force. It isn't a vector equation. To get the magnitude of a cross product, you need to include the sine of the angle between the vectors, \$|\vec{a}\times\vec{b}|=|\vec{a}||\vec{b}|\sin\theta\$. | |
| Dec 21, 2018 at 21:02 | comment | added | Vyun | But if cross-product gives us already the perpendicular vector, then why do we multiply it again with sine ? | |
| Dec 21, 2018 at 20:58 | history | answered | The Photon | CC BY-SA 4.0 |