Timeline for Root Locus, Gain in Feedback Loop. Need help
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 20, 2019 at 19:27 | comment | added | Ibnc | What I mean by G(s) is 1/(s+3)(s+4) * K/s(s+1). Then use poles from this new fucntion. | |
| Jan 17, 2019 at 10:50 | comment | added | LvW | The characteristic equation is: 1+LG=0 with Loop Gain LG=G*H (G: Forward block and H=Feedback block) | |
| Jan 17, 2019 at 10:45 | comment | added | LvW | Ibns....regarding your comment/question (C.E=1+G(s)): No, you must NOT use the poles of G(s) . Remember the name: ROOT locus. You are calculating the ZEROS of the C.E. . And these zeroes are identical to the poles of the closed-loop function. My recommendation: Do not simply believe answers but try to verify the evidence of all statements. | |
| Jan 17, 2019 at 10:36 | comment | added | LvW | Ibns....I think, the comment from Henrique A.B.P is NOT CORRECT. The so called "loop gain" - which is the total gain around the loop - is the product of all transfer functions witin the loop - including the minus sign at the summing node. | |
| S Jan 17, 2019 at 5:49 | history | suggested | HermitianCrustacean | CC BY-SA 4.0 |
Grammar corrections and MathJax fanciness.
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| Jan 17, 2019 at 1:23 | review | Suggested edits | |||
| S Jan 17, 2019 at 5:49 | |||||
| Jan 17, 2019 at 1:18 | vote | accept | Ibnc | ||
| Jan 20, 2019 at 19:23 | |||||
| Jan 17, 2019 at 0:28 | comment | added | habp1992 | Yes for your both questions. | |
| Jan 17, 2019 at 0:00 | comment | added | Ibnc | I understand now everything, thank you. So just to summarize, we draw root locus for characteristic equation? So if C.E. is 1+G(s), we use poles from G(s)? | |
| Jan 16, 2019 at 23:31 | comment | added | habp1992 | Your transfer function of open loop is what relates your output to your input without the feedback. In your case it will be only Y(s)/Xr(s) = 1/((s+3)(s+4)). | |
| Jan 16, 2019 at 23:18 | comment | added | Ibnc | Ah, thank you. Actually I did draw a root locus for that equation but I wasnt sure. I have another question in that case. What is the transfer function of open loop system in my example? | |
| Jan 16, 2019 at 23:15 | review | First posts | |||
| Jan 16, 2019 at 23:39 | |||||
| Jan 16, 2019 at 23:12 | history | answered | habp1992 | CC BY-SA 4.0 |