Timeline for Is this a correct way to route current away from breadboard?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 1, 2019 at 11:57 | vote | accept | FourJoltsYouSummerPulse | ||
| Jan 30, 2019 at 16:02 | comment | added | zwol | @FourJoltsYouSummerPulse I'm sorry, I don't know how to design overcurrent/voltage protection circuits in detail, I only know you probably need one in this application. | |
| Jan 30, 2019 at 8:06 | comment | added | FourJoltsYouSummerPulse | @analogsystemsrf I believe R (10 ohms) should be put on the power line (red in schema) and C (100uF) between power and ground. And this should be done before connecting to breadboard, correct? | |
| Jan 30, 2019 at 8:03 | comment | added | FourJoltsYouSummerPulse | @zwol should I put fuses on both power and ground wires (connecting to the breadboard) and also maybe a diode on ground (to make sure the 'amps' flow the right way - to ground)? | |
| Jan 30, 2019 at 3:53 | comment | added | analogsystemsrf | Add an R+C filter into the VDD to the breadboard: 10 ohms and 100uF, to help hold the Breadboard voltage steady during motor spikes. | |
| Jan 29, 2019 at 19:10 | comment | added | zwol | For additional safety, you can put some sort of overcurrent protection device at the point where the power cables connect to the breadboard. Voltage regulation with transient spike suppression is probably even more important; motors can generate nasty transients when they start and stop moving. (Make sure the power supply is rated to handle a 3A motor specifically, too.) | |
| Jan 29, 2019 at 15:01 | history | edited | HandyHowie | CC BY-SA 4.0 |
added 87 characters in body
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| Jan 29, 2019 at 14:56 | history | answered | HandyHowie | CC BY-SA 4.0 |