Timeline for How do select capacitor for 400A surge currents?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 3, 2019 at 13:10 | vote | accept | Fat Diode | ||
| Mar 23, 2019 at 6:00 | history | tweeted | twitter.com/StackElectronix/status/1109334107195142144 | ||
| Mar 23, 2019 at 3:25 | comment | added | Robert Endl | Sounds like what you want is a DC link or snubber capacitor. | |
| Mar 22, 2019 at 17:00 | comment | added | analogsystemsrf | 400 amps in a triangular waveform, Trise of 0.5 microseconds. If the circuit has 20 nanoHenry of inductance (about an inch of wire), the voltage will be V = L * dI/dT = 20nH* 400amp/500nSec = 8000/500 = 16 volts. Do you care? | |
| Mar 22, 2019 at 16:27 | comment | added | Spehro 'speff' Pefhany | Is that a theoretical SPICE current or is it realistic in terms of what might actually occur? 400A through 220nF implies dv/dt of almost 2000V/\$\mu\$s, rather high. | |
| Mar 22, 2019 at 16:17 | answer | added | D.A.S. | timeline score: 2 | |
| Mar 22, 2019 at 15:02 | comment | added | Fat Diode | Added some extra information. | |
| Mar 22, 2019 at 15:02 | history | edited | Fat Diode | CC BY-SA 4.0 |
added 458 characters in body
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| Mar 22, 2019 at 14:49 | comment | added | Vladimir Cravero | Hi, can you also post your schematic and give a bit of insight? Did you use an ideal cap in your spice simulation, or did you add some series resistance? | |
| Mar 22, 2019 at 14:42 | history | asked | Fat Diode | CC BY-SA 4.0 |