Wikipedia: ... for the case of a hypothetical 1 mA, 500 Ω movement
This means that the meter reads full scale when 1 mA is flowing through it. The voltage across the meter will be \$ V = IR = 1m \cdot 500 = 500 \ \text {mV} \$. So it will read full scale if connected across a 500 mV voltage source too.
simulate this circuit – Schematic created using CircuitLab
Figure 1. The example meter has an internal resistance of 500 Ω and will read full scale with 1 mA through it.
... on a 1 A range, the shunt resistance would be just over 0.5 Ω.
Figure 2. R1 "shunts" most of the current around the ammeter.
To measure 1 A without damage to the meter we need to shunt 499 mA around the meter while 1 mA runs through it. We have already calculated that the voltage drop across the meter will be 500 mV at full scale so we can calculate R1 as $$ R_1 = \frac {V}{I} = \frac {0.5}{0.999} = 0.5005 \ \Omega $$
The combined meter and shunt is always wired in series with the circuit being measured.
Figure 3. Correct measurement technique.
From the comments:
You need to connect your multimeter in series when you are measuring current. – The Photon
But this article talks of something parallel – Shlok Vaibhav
It is describing the meter being in parallel to the shunt which is in series with the circuit being measured. Hopefully this is clear now.