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Oct 26, 2013 at 2:45 vote accept boardbite
Oct 10, 2012 at 20:15 comment added Dave Tweed @stevenvh: Actually, they are; the original question was posed in terms of current pulses. For this type of general feasibility question, linearizing the equations (while understanding that this is an approximation) is perfectly legitimate.
Oct 10, 2012 at 19:53 comment added stevenvh @Dave - You don't need resistors because you're assuming constant current sources/sinks. That's how you get linear equations instead of exponential. True, I added resistors which aren't in the question, but you add current sources which aren't there either :-)
Oct 10, 2012 at 19:36 history rollback Dave Tweed
Rollback to Revision 2
S Oct 10, 2012 at 18:45 history suggested boardbite CC BY-SA 3.0
re-added statement that was made by @Dave Tweed
Oct 10, 2012 at 18:38 review Suggested edits
S Oct 10, 2012 at 18:45
Oct 10, 2012 at 18:24 history edited Dave Tweed CC BY-SA 3.0
update answer to track changes in question
Oct 10, 2012 at 18:05 history answered Dave Tweed CC BY-SA 3.0