Timeline for Pulse-powering heavy loads with a coin cell
Current License: CC BY-SA 3.0
6 events
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| Oct 11, 2012 at 6:18 | history | edited | stevenvh | CC BY-SA 3.0 |
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| Oct 10, 2012 at 20:11 | comment | added | Dave Tweed | A resistor is just one of many ways to control current. Appropriate active circuits will be much more efficient. The original question was about the feasibility of the general concept. | |
| Oct 10, 2012 at 19:51 | comment | added | stevenvh | @Dave - Are you going to short-circuit the capacitor over the LED? You'll have a lot more than 25 mA then. Granted, only for a short time, but nevertheless the LED wouldn't like it. For charging I'll have to see if I can make use of the battery's internal resistance, but IMO a series resistance will still be needed: otherwise the capacitor discharge to 2 V will also brown-out the microcontroller, if it's directly connected. Remember that we don't have a hard 3 V, but a 3 V with a series resistance, which will take the difference between the 3 V and the capacitor's 2 V. | |
| Oct 10, 2012 at 19:45 | history | edited | stevenvh | CC BY-SA 3.0 |
added 48 characters in body
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| Oct 10, 2012 at 19:45 | comment | added | Dave Tweed | Where did all these resistors come from? They're certainly not part of the original question, and if you were really concerned about running something from a coin cell, you wouldn't be wasting a significant fraction of your energy in resistors! | |
| Oct 10, 2012 at 18:43 | history | answered | stevenvh | CC BY-SA 3.0 |