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Aug 26, 2017 at 9:19 answer added next-hack timeline score: 0
Aug 26, 2017 at 8:52 answer added Wim timeline score: 0
Oct 11, 2012 at 17:57 vote accept Digital Brent
Oct 11, 2012 at 13:13 answer added Olin Lathrop timeline score: 11
Oct 11, 2012 at 7:41 answer added stevenvh timeline score: 9
Oct 11, 2012 at 3:11 answer added Michael Karas timeline score: 16
Oct 11, 2012 at 3:01 history tweeted twitter.com/#!/StackElectronix/status/256228012708737024
Oct 11, 2012 at 0:52 comment added apalopohapa It's probably just to attenuate current transients when discharging the input capacitance of the transistor when closing the switch. It will consequently also slow down the turn-off time a bit.
Oct 11, 2012 at 0:49 comment added Chris Laplante When the switch is closed, the 10K and 1K resistor form a voltage divider.
Oct 11, 2012 at 0:13 history asked Digital Brent CC BY-SA 3.0