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May 2, 2019 at 0:05 vote accept Isaac Lubow
May 2, 2019 at 0:05
Apr 25, 2019 at 21:53 history edited Jasen Слава Україні CC BY-SA 4.0
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Apr 25, 2019 at 21:28 comment added Jasen Слава Україні 9V might be a bit much for the LM2596S module as the module seet the input voltage added to the output voltage, LM2596HVS would be better, or XL6009 (just added) gives even more flexibility unfortunately these modules are inexpensive only if you can wait several weeks,
Apr 25, 2019 at 11:22 comment added pipe @IsaacLubow It can't - it can only make the voltage lower. You need at least 20 volts to light up the LEDs, but likely more (so can't even use two 9V batteries in series). Look at the LM2596S option, it works well with 9V input too.
Apr 24, 2019 at 17:46 comment added Isaac Lubow Can you point me to a schematic where an LM317 turns 9VDC into the constant current needed for this setup?
Apr 23, 2019 at 22:38 comment added Jasen Слава Україні @IsaacLubow, yes, that is suitable.
Apr 23, 2019 at 19:26 comment added Isaac Lubow Can I do this with an LM317 like this one mouser.com/ProductDetail/ON-Semiconductor/…?
Apr 23, 2019 at 17:49 vote accept Isaac Lubow
Apr 24, 2019 at 17:58
S Apr 23, 2019 at 13:15 history suggested angussidney CC BY-SA 4.0
Clean up punctuation, grammar, and formatting.
Apr 23, 2019 at 12:40 review Suggested edits
S Apr 23, 2019 at 13:15
Apr 23, 2019 at 8:02 comment added TooTea Or alternatively, connect the switch between the anodes and the current source instead of the ground. That way there will be no power draw when no LEDs are lit, and it will be easier to route if you want the LED bar to grow clockwise/to the right when the switch is turned clockwise.
Apr 23, 2019 at 3:22 history edited Jasen Слава Україні CC BY-SA 4.0
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Apr 23, 2019 at 2:52 history edited Jasen Слава Україні CC BY-SA 4.0
added 151 characters in body
Apr 23, 2019 at 2:41 history answered Jasen Слава Україні CC BY-SA 4.0