Timeline for Common base bias divider resistances
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 23, 2019 at 21:32 | comment | added | jonk | Hopefully, it helps a bit. Feel free to ask questions there, too. Or just ask a new one. | |
| Apr 23, 2019 at 21:32 | vote | accept | TrivialCase | ||
| Apr 23, 2019 at 21:31 | comment | added | TrivialCase | @jonk Thanks, that looks very helpful! My hope was to figure out how to design a common base amplifier instead of just analyze an existing one - and it looks like that post does just that. Not sure why, but I can't find a book that details design of common base. | |
| Apr 23, 2019 at 21:29 | comment | added | jonk | Well, read the above link I provided and see if it helps. | |
| Apr 23, 2019 at 21:28 | comment | added | TrivialCase | Well, yes. But here I thought something had gone mysteriously wrong because I was dumb and not thinking of the equiv value of the resistance in the divider for some reason. It's like if I had forgot how to add numbers while learning how to solve PDEs... | |
| Apr 23, 2019 at 21:26 | comment | added | jonk | So, are you interested how the common base functions? You could examine this answer I wrote, earlier. I've oriented the schematic better, so it might make more sense. | |
| Apr 23, 2019 at 21:25 | comment | added | TrivialCase | Evidently it's been a long day. Clearly 50k || 100k = 33k. No clue what I was thinking there. | |
| Apr 23, 2019 at 21:25 | answer | added | D.A.S. | timeline score: 1 | |
| Apr 23, 2019 at 21:22 | comment | added | jonk | You are going to have a lot of trouble if you don't follow why the \$50\:\text{k}\Omega\$ resistor and the \$100\:\text{k}\Omega\$ resistors set between two power rails make up \$50\:\text{k}\Omega\mid\mid 100\:\text{k}\Omega\approx 33.3\:\text{k}\Omega\$. That's a basic element you need to follow right away. Next is that the common base arrangement should, if oriented well for reading, look a lot like a CE arrangement except that the signal is removed from the input capacitor with that end of the capacitor then grounded, instead. | |
| Apr 23, 2019 at 21:15 | history | asked | TrivialCase | CC BY-SA 4.0 |