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Jun 11, 2020 at 15:10 history edited CommunityBot
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May 28, 2019 at 3:26 history edited jonk CC BY-SA 4.0
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May 20, 2019 at 19:44 history edited jonk CC BY-SA 4.0
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May 20, 2019 at 18:11 comment added jonk @ttsiodras There's more I could have added. If you select a small enough value for \$C_1\$ (where \$R_1\cdot C_1\$ is on the order of \$t_\text{on}+t_\text{off}\$, the circuit will self-trigger once the inductor exhausts its stored energy. (The value of \$C_1\$ can vary over a small range near that point without much affect on the frequency.) If you decrease \$C_1\$ still further, it stops being in discontinuous mode and operates entirely differently. I avoided exploring those areas because of time.
May 20, 2019 at 18:03 comment added jonk @ttsiodras Okay. That's embarrassing. But it's still nice to hear. Thanks for the kind words!
May 20, 2019 at 17:58 comment added ttsiodras Oh God, as if your answer wasn't already impressive enough! Thanks so much - that was it! All mysteries solved... and I can honestly say, this is the best answer I have ever received across all of StackExchange.
May 20, 2019 at 16:53 history edited jonk CC BY-SA 4.0
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May 20, 2019 at 16:52 comment added jonk @ttsiodras The circuit I provided is an exact match with yours. Except I didn't include the switch. I appreciate the thanks! So thanks for that! I'll write a note about LTspice in my answer regarding "direction of current" that may help you, too. Look for it.
May 20, 2019 at 11:29 history edited jonk CC BY-SA 4.0
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May 20, 2019 at 7:16 comment added ttsiodras Thank you, I very much appreciate the work you put into this. Wish I could vote it more than once! I see your LTSpice design is a bit different to mine - when I return back home (currently at work) I will replace my components with yours to see which one makes the difference in the way the inductor current flows. Many thanks again.
May 20, 2019 at 7:13 vote accept ttsiodras
May 20, 2019 at 5:49 history answered jonk CC BY-SA 4.0