Timeline for Find instant in which diode starts conducting in transformer full wave rectifier
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 27, 2019 at 16:46 | comment | added | D.A.S. | Uber Answer: No solution as Diodes do not have a Peak Inverse Voltage rating of >=10kV with a forward Vf=0.8. It would have to be at least 10 diodes in 1 thus Vf >8V so not possible to have Vf=0.8V with Vr=10kV=PIV rating | |
| Jun 27, 2019 at 16:32 | comment | added | D.A.S. | For Uber Analog EE's, what is the diode bulk resistance, Rs for that PIV diode to conduct enough current to reach 0.8V ? to at least 1 sig.fig. | |
| Jun 27, 2019 at 16:20 | comment | added | D.A.S. | Mr Roughbeast. Now for an expert question. ( for fun) What transformer parameters (L=?, coupling coefficient=?) with at least 1 sig.fig) are necessary to achieve Vf=0.8A say for 1kOhm load and what must be the PIV rating.? (min) | |
| Jun 27, 2019 at 15:59 | comment | added | D.A.S. | Mr Sinno... In real world , we say Vf=0.8V @ If= (Vs-0.8)/R which is more than the vanish point or near 0, so the time delay to reach this voltage at some phase is actually a tad larger. Vf=0.8 is 1A for a typ. 1N4005 power diode. but for now neglect this. | |
| Jun 27, 2019 at 15:51 | vote | accept | CommunityBot | ||
| Jun 27, 2019 at 15:18 | history | answered | WhatRoughBeast | CC BY-SA 4.0 |