Timeline for Sending flyback current to another inductor using crossed diodes
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 5, 2019 at 7:23 | comment | added | Andy aka | What is the schematic intended to show? | |
| Jul 5, 2019 at 4:38 | answer | added | hacktastical | timeline score: 2 | |
| Jul 5, 2019 at 0:06 | comment | added | Xylord | @BruceAbbott I want the electromagnets to follow this cycle: EM1 ON - EM2 OFF - 0.00625 s EN1 OFF - EM2 ON - 0.00625 s The voltage across the electromagnets may vary, but overall this should still be close to a square wave. So I'd use the PWM to both control the strength of the electromagnets, and to switch them on and off at 80Hz. I was thinking of using MOSFETs. | |
| Jul 5, 2019 at 0:01 | comment | added | Xylord | @Transistor So, if Q1 opened and Q2 closed, the current through L1 will simply come down as it would if the L2 branch wasn't there at all... Yes this makes sense. So all the magnetic energy stored in L1 will be lost, as heat in R1? And this is inevitable? | |
| Jul 4, 2019 at 21:37 | comment | added | Bruce Abbott | Do you want each electromagnet to turn on and off at 80Hz, or is the PWM used to adjust the strength of one relative to the other? | |
| Jul 4, 2019 at 21:06 | comment | added | Transistor | If you drag D2 to the left of D1 you will see that you just have regular snubber diodes across each inductor. There is no cross-feed of current from one to the other. Your little plan isn't going to work. | |
| Jul 4, 2019 at 20:59 | history | asked | Xylord | CC BY-SA 4.0 |