Timeline for How to replace a potentiometer with a digital solution in a buck feedback loop?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Dec 23, 2019 at 16:07 | vote | accept | Askerman | ||
| Dec 22, 2019 at 11:57 | comment | added | Andy aka | No, don’t be silly, the feedback pin regulates to about 1.25 volts. Only under some fault conditions will the feedback pin go significantly above 1.25 volts and that can be caught by a zener diode. Read the data sheet it specifically tells you what the FB pin has on it when in regulation. | |
| Dec 22, 2019 at 9:21 | comment | added | Askerman | As is, I turn R2 to provide the feedback pin with up to 23V, if I crank the wiper up, where the 47k is 0ohms (relative to FB). So the R1 is seeing 23V in the voltage division. In order to replace the R1 with a digital pot and have it work the same way, won't I still have to be able to deliver up to 23V to the FB pin, and thus expose R1 to 23V? | |
| Dec 20, 2019 at 10:30 | history | edited | Andy aka | CC BY-SA 4.0 |
added 354 characters in body
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| Dec 20, 2019 at 9:43 | history | answered | Andy aka | CC BY-SA 4.0 |