Timeline for How to find the apparent power absorbed by a three phases load?
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 23 at 10:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 24, 2023 at 22:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 13, 2023 at 19:10 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 31, 2022 at 11:06 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 1, 2022 at 9:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 4, 2022 at 0:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 29, 2021 at 18:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 31, 2021 at 0:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 22, 2020 at 17:27 | answer | added | user238462 | timeline score: 1 | |
| Jan 22, 2020 at 17:17 | comment | added | Kevin | Yes, totally. Thanks! | |
| Jan 22, 2020 at 17:13 | comment | added | X J | Magnitude of (1-j) is sqrt(2), then the denominator is 2. Does this make sense? | |
| Jan 22, 2020 at 17:09 | comment | added | Kevin | It seems I'm having a little bit trouble getting to 135kVA. Where does the immaginary term go? | |
| Jan 22, 2020 at 17:07 | comment | added | X J | 300^2 / |sqrt(2)(1-j)| * 3 = 135 KVA ! | |
| Jan 22, 2020 at 16:57 | history | asked | Kevin | CC BY-SA 4.0 |