Timeline for High side power consumption measure reversible circuit
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Apr 5, 2020 at 8:30 | history | edited | vtolentino | CC BY-SA 4.0 |
added 915 characters in body
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| Apr 5, 2020 at 7:55 | comment | added | vtolentino | Since the current flowing through the load side's diode causes a voltage drop equal to \$V_{drop} = I_{load}\cdot R_S + V_{D,fwd}\$, the uC and the sensor will draw current from the supply rail with the higher voltage. I will update my answer, in case you still want some active switching. | |
| Apr 5, 2020 at 7:25 | comment | added | Alexey Kamenskiy | I think that would still cause some power going through the diode on load side due to diode internal resistance. Which is exactly what I would like to avoid as this is intended for rather precise measurements. | |
| Apr 5, 2020 at 7:17 | history | answered | vtolentino | CC BY-SA 4.0 |