Timeline for High-side switch to disconnect battery
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 21, 2020 at 8:21 | comment | added | Reto | I will try the NMOS solution as current will be high. | |
| May 21, 2020 at 1:22 | comment | added | user57037 | This is a good complement to the other solution which is PMOS based. I guess if the current requirement is high NMOS could be the better choice. OP did not say much about current. | |
| May 21, 2020 at 1:13 | comment | added | eceforge | That's fair, I was mostly trying to make the point that you can indeed do high-side switching of a MOSFET, which the person asking seemed to be confused about. I've update the schematic with more details on the gate-drive circuitry. | |
| May 21, 2020 at 1:11 | history | edited | eceforge | CC BY-SA 4.0 |
Adding gate-drive logic as requested.
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| May 20, 2020 at 23:56 | comment | added | user57037 | Why don't you show the logic that controls the high-side gate driver. You need to somehow detect when the 24V supply is absent. How would you do that if the output of your high-side switch is directly connected to 24V? | |
| May 20, 2020 at 23:42 | comment | added | eceforge | I'm suggesting driving the gate with a charge-pump gate driver IC in the text of the answer, that's why I didn't draw an explicit connection to the gate here. I'm not sure sure what you mean that hooking up V2 like that won't work, happy to change if I missed something though. | |
| May 20, 2020 at 23:37 | comment | added | user57037 | The way you connected V2 is not going to work, either. You will see if you try to finish the circuit. | |
| May 20, 2020 at 23:17 | comment | added | user57037 | You don't show the gate connection. This can work but it is not very helpful without providing all the tricky gate drive details. | |
| May 20, 2020 at 23:13 | history | answered | eceforge | CC BY-SA 4.0 |