Timeline for How to drop the voltage slightly (~100mV) for a MCU mostly in deep sleep?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| May 22, 2020 at 7:54 | comment | added | Russell McMahon♦ | 5 x 100 mA capable regulators in parallel would give you 500 mA capability at about 0.5 uA iQ and about $3 cost. | |
| May 22, 2020 at 7:54 | comment | added | Russell McMahon♦ | The MAX 600x family of shunt regulators has a 1uA typical 0.5 uA min operating (Cathode) current. datasheets.maximintegrated.com/en/ds/MAX6006A-MAX6009B.pdf Two of appropriate voltage in series may allow you low drain mode to work OK, switching to another mode on throttle-up. || A S1318 family regulator can have 55 nA drain, 0.054V dropout [!!!] and bearable cost. (About $US1) | There are "any number" of regulator rated at 100 mA output and well under 0.1V dropout and sub uA Iq. | | |
| May 21, 2020 at 11:17 | answer | added | vtolentino | timeline score: 1 | |
| May 21, 2020 at 10:26 | comment | added | DurandA | @SpehroPefhany I edited my question. | |
| May 21, 2020 at 10:25 | history | edited | DurandA | CC BY-SA 4.0 |
add microcontroller current requirements
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| May 21, 2020 at 2:05 | comment | added | Spehro 'speff' Pefhany | This can't reasonably be answered without information about the minimum/maximum current draw of your circuit. You could also consider using a different microcontroller. Probably an LDO is your best bet. | |
| May 21, 2020 at 1:21 | answer | added | Ocanath | timeline score: 0 | |
| May 21, 2020 at 0:47 | history | asked | DurandA | CC BY-SA 4.0 |