Timeline for Superposition of energy
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Jun 1, 2020 at 11:40 | comment | added | Marcus Müller | No need to apologize, nothing bad happened! Yes, if there was superposability, then the equality \$I_1^2R +I_2^2R = (I_1+I_2)^2R\$ would hold, but that equation is plainly wrong. And I've kind of said that five or so times now – and I have what I thought to be an intuitive example... | |
| Jun 1, 2020 at 11:35 | comment | added | cccube | Sorry, Marcus, to make sure I understood you correctly, are you saying that ((I1+I2)^2)*R = Power is not a superposition of I1 and I2? Why can't that be the definition of superposable sources, as with the other answer? Sorry about that mistake with power, of course you are right there. | |
| Jun 1, 2020 at 10:46 | comment | added | Marcus Müller | energy·time is not power, power is energy/time; but that doesn't matter here. The power dissipated in your resistor is P=(I_R)²·R, right? so there's a square in there. That means the thing isn't linear w.r.t. to the current flowing throw this. Superposability does not exist for power nor energy, because it simply doesn't. (A+B)² is not the same as A²+B². It's really that simple, high school math that you're arguing against. | |
| Jun 1, 2020 at 10:40 | comment | added | cccube | I think these are scalars of one another, right? i.e. energy*time = power... OK close the parenthesis). My point is that energy (or power, I think) is superposable in a given circuit, whereas you mention for some reason that it is not. My current understanding is that if voltage or current sources are orthogonal, i.e. their composition is 0, then energy remains superposable. | |
| Jun 1, 2020 at 10:36 | comment | added | cccube | I think you explained your point very well, I just wanted to know if the orthogonality of voltage sources for energy superposability was the same for current sources, which, to my limited experience thus far, often behave differently. I was pleased to see from Andy's answer above that they are the same, as far this specific question goes. Now, for your point about current sources pointing in different directions, I think you are completely right, their direction matters for the energy dissipated over a given resistor (in this case R1. I also keep mentioning energy and you power...cont. below | |
| Jun 1, 2020 at 10:26 | comment | added | Marcus Müller | so, it does matter which direction I1 and I2 are, because that changes the value of the composition, right? So I'm a bit confused about what you're telling me. | |
| Jun 1, 2020 at 10:21 | comment | added | Marcus Müller | @cccube but power is not superposable, it's really that simple. R1 in the above constellation dissipates 0W, not 2W. I think that is kind of obvious, or did I explain it badly? (please do tell me if I explained it badly!) | |
| Jun 1, 2020 at 10:06 | comment | added | cccube | Couple of things. I am not sure what the "No" at the beginning of your answer corresponds to. I also don't think your answer is all that helpful because the orthogonality of I1 and I2 still apply. In other words, it should not matter in what direction your current sources are pointed - if the composition of I1 and I2 is 0, then energy is superposable. | |
| May 31, 2020 at 13:23 | history | edited | Marcus Müller | CC BY-SA 4.0 |
added 378 characters in body
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| May 31, 2020 at 13:16 | history | answered | Marcus Müller | CC BY-SA 4.0 |