Timeline for Why is impedance represented as a complex number rather than a vector?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jul 10, 2020 at 8:25 | comment | added | dronir | @JShorthouse I guess mainly because complex numbers make the math much easier than other ways to compute the same result. | |
| Jul 9, 2020 at 21:42 | comment | added | Voltage Spike♦ | The vectors are in the complex space, so the y axis is the imaginary part, the x axis is the real part. hackmath.net/en/calculator/complex-number | |
| Jul 9, 2020 at 21:35 | comment | added | JShorthouse | I am asking specifically why the property of j = sqrt(-1) is needed, meaning that j * j = -1 (which wouldn't happen with a vector representation). There must be some reason why this property is needed and therefore why complex numbers are used, I just can't figure out how this property is needed for impedance calculations. | |
| Jul 9, 2020 at 21:31 | comment | added | Voltage Spike♦ | Vectors are used, it depends on what system is used to represent the phase. Either the phase can be represented as a vector, and actually some forms of AC analisys only use vectors. allaboutcircuits.com/textbook/alternating-current/chpt-2/… | |
| Jul 9, 2020 at 21:28 | history | edited | Voltage Spike♦ | CC BY-SA 4.0 |
added 158 characters in body
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| Jul 9, 2020 at 21:27 | comment | added | JShorthouse | Yes, I understand what the imaginary part represents but I don't understand why a complex number is used. Why could a vector with two dimensions not instead be used to represent this? | |
| Jul 9, 2020 at 21:26 | history | answered | Voltage Spike♦ | CC BY-SA 4.0 |