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Jun 16 at 15:01 comment added flodis The problem with the suggested circuit is, as soon as the upper MOSFET conducts Ugs will drop and the transistor will be in the active region not at all turned on. The gate driver like the IRS20752LPBF you studied does not depend on the high side voltage. The capacitor of the driver is charged from Vcc everytime the low side conducts to GND. The high side driver floats with the charged capacitor voltage to operate the gate voltage relative to the source pin. In the datasheet example Vcc determine the capacitor voltage but it can be charged from some other voltage as desired.
Aug 31, 2020 at 1:56 history answered FrankTheTank360 CC BY-SA 4.0