Timeline for EE-SX1140 datasheet confusion
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 29, 2020 at 20:32 | vote | accept | GRASBOCK | ||
| Sep 29, 2020 at 20:32 | comment | added | GRASBOCK | That explained it very well nevertheless. Thank you kindly | |
| Sep 29, 2020 at 14:43 | comment | added | Andy aka | Yes, look at the small diagram in the data sheet under the response time graph. I didn't follow what you meant in your 2nd sentence. If you mean why is the rise/fall time greater when the collector saturates more, it's down to the fact that to get a deep saturation requires a higher collector/emitter load resistor and, given that the "base" is tickled only by photons, the capacitance around the base can be problematic with a bigger changing output voltage and a load resistor that is "weaker". | |
| Sep 29, 2020 at 14:34 | comment | added | GRASBOCK | I see now. So then it's safe to connect a 100Ohm RL. Just out of curiosity: Why is the rise time larger with a lower collector-emitter voltage? I thought smaller voltages make electronics faster because risetime can be smaller. | |
| Sep 29, 2020 at 14:25 | comment | added | Andy aka | @RIJIK Yes, there will be. Opto's are not that great for high speed stuff. Look at the CE saturation spec - it's at a collector current of 0.1 mA and that implies an RL of around 50 kohm and 50 kohm will be poor for speed (in fact it isn't even shown on the graph in my answer). | |
| Sep 29, 2020 at 14:24 | comment | added | GRASBOCK | I thought the voltage drop across collector-emitter would be constant on saturation. So there is 4.5V across collector-emitter? | |
| Sep 29, 2020 at 11:39 | history | answered | Andy aka | CC BY-SA 4.0 |