Timeline for How is this pole compensated
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2020 at 18:31 | comment | added | RAN | Also in the open loop transfer function which I have posted, the phase changes by 90 degrees, then it trails off to 180 degrees due to the second pole, which is already at very high frequency | |
| Nov 16, 2020 at 16:04 | comment | added | RAN | There are two poles in the open loop response, but the second pole is further away than the unity gain frequency, hence I have approximated the open loop response of that of a first order. The open loop second pole is not close to the closed loop peaking response. | |
| Nov 15, 2020 at 17:09 | comment | added | user173271 | @RAN See edit.. | |
| Nov 15, 2020 at 17:08 | history | edited | user173271 | CC BY-SA 4.0 |
Adding extra information
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| Nov 15, 2020 at 8:48 | comment | added | RAN | The last paragraph in your answer makes sense, that the closed loop gain reduces as Rf is shorted out. But why isnt it apparent from the equations which I put in my question? The way i see it is, the complex conjugate poles are not really cancelled, but they are masked by a stronger dominant pole introduced by the feedback capacitor. Am I correct? Also please can you comment on the analysis I have shown? Are the transfer functions correct? | |
| Nov 14, 2020 at 11:56 | history | answered | user173271 | CC BY-SA 4.0 |