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Dec 8, 2020 at 14:35 comment added pjc50 This is one of those things where "how does it work really" is very complicated; for stackoverflow purposes might consider this a duplicate of the clarified question at electronics.stackexchange.com/questions/535548/…
Dec 3, 2020 at 19:45 history edited Zhelyazko Grudov CC BY-SA 4.0
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Dec 3, 2020 at 19:39 history edited Zhelyazko Grudov CC BY-SA 4.0
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Dec 3, 2020 at 19:30 comment added Zhelyazko Grudov Hi Chris, funnily enough I had looked at that already! Thank you for sharing in any case. He does mention there loss of kinetic energy and equates it to loss in potential energy which I do not understand, however my main conclusion is why a resistor does not drop a fixed amount of voltage but a variable one depending on battery voltage. If you use the analogy of gravity and friction, would a small amount of friction drop any amount of potential energy? Would it not drop a fixed amount depending on how significant the friction is?
Dec 3, 2020 at 18:35 comment added Chris Stratton "How does resistance actually work" is clearly electrical physics, but it's also physics physics so it's worth having a look elsewhere, for example this might be interesting: physics.stackexchange.com/questions/406451/… Nominally this is the kind of thing for which basic references such as textbooks, etc should be the starting point, unfortunately wikipedia doesn't seem to have much that's readily found. Some additional web searching may be worthwhile.
Dec 3, 2020 at 18:08 answer added analogsystemsrf timeline score: -1
Dec 3, 2020 at 17:43 answer added Fredled timeline score: 0
Dec 3, 2020 at 13:18 comment added Zhelyazko Grudov I understand the use of Ohm's law. What I do not understand is why the resistor behaves in this way? I am familiar with the PN junction, basics of how the electric field creates regions of higher and lower potential and why electrons move from high to low potential. Presumably, the electron will seek to drop all this potential energy if a conducting path is open. But in the diode example in drops only a fixed amount, not so in the case of a resistor. How come?
Dec 3, 2020 at 12:59 answer added JRE timeline score: 2
Dec 3, 2020 at 12:30 comment added Justme Ohm's law is pretty fundamental for describing how resistances work. Diodes can be modeled many ways, including simple models that do have a resistance and some treshold voltage.
Dec 3, 2020 at 12:26 review First posts
Dec 17, 2020 at 12:26
Dec 3, 2020 at 12:25 history asked Zhelyazko Grudov CC BY-SA 4.0