Timeline for How can I convert from voltage TDR into impedance TDR
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Mar 11, 2021 at 14:31 | comment | added | ron398 | Hello 10ppb,I have implemented an official keysight manual shown bellow. they say its impedance at every point(time varying location) youtube.com/watch?v=U3be5KkGmAc&t=121s | |
| Mar 11, 2021 at 13:50 | comment | added | 10ppb | None of the symbols in your formula appear in either schematic, so I don’t know what they refer to. However, if V is the voltage drop across a 2-terminal component A in any branch, R is a resistor in the same branch, and I is (voltage drop across R)/R, then it is certainly true that V/I is the impedance at A (the voltage across A divided by the current through A). This does not tell us the impedance anywhere else in the circuit. | |
| Mar 11, 2021 at 13:47 | history | edited | JRE | CC BY-SA 4.0 |
added 1 character in body; edited title
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| Mar 11, 2021 at 12:59 | answer | added | D.A.S. | timeline score: -1 | |
| Mar 11, 2021 at 12:50 | comment | added | D.A.S. | I fully appreciate how some people pronounce english words differently and my spelling is often poor, yet I recommend Grammarly for anyone. | |
| Mar 11, 2021 at 12:50 | comment | added | Andy aka |
Try using mathjax i.e. \$Z = \dfrac{V}{\frac{\delta V}{R}}\$ = \$Z = \dfrac{V}{\frac{\delta V}{R}}\$
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| Mar 11, 2021 at 12:43 | history | asked | ron398 | CC BY-SA 4.0 |