Timeline for Find Vo of an op-amp circuit
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 9, 2021 at 11:06 | vote | accept | Aeden Schmidt | ||
| Apr 9, 2021 at 7:49 | comment | added | jonk | @AedenSchmidt Just grab any two resistor values in series and place any two arbitrary voltage sources at either end. Work out the formula for the midpoint voltage. You'll see very quickly. | |
| Apr 9, 2021 at 7:46 | comment | added | Aeden Schmidt | @jonk im afraid im not familiar with that, thanks for the info, I will try to look into it more. | |
| Apr 9, 2021 at 7:40 | comment | added | jonk | @AedenSchmidt V3 is the opamp output. You have two voltage sources and two resistors on the left side. You multiply one source by the resistance of the other source and add the product of the other source and its opposing resistance and then divide all that by the sum of the two resistances. Basic divider formula. | |
| Apr 9, 2021 at 7:36 | comment | added | Aeden Schmidt | @jonk may i ask where did V3*100k come from? | |
| Apr 9, 2021 at 7:29 | comment | added | jonk | @AedenSchmidt V+ is (V3*100k+.1 V*100k)/200k. It's a simple divider between two sources. I think you got that wrong, already. | |
| Apr 9, 2021 at 7:13 | comment | added | Aeden Schmidt | I just cant get it, I tried (V1-V+)/R1 = (V+ - V3)/R2 and (V+-V3)/R2 = (V3-V-)/R4 and still got it wrong, is my equation wrong? | |
| Apr 9, 2021 at 7:04 | comment | added | jonk | I got the same for the ideal opamp output: (.198/2)/(1-1.98/2). | |
| Apr 9, 2021 at 6:48 | history | answered | Spehro 'speff' Pefhany | CC BY-SA 4.0 |