Timeline for Pre-regulator sizing
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 20, 2021 at 8:49 | vote | accept | Neeko | ||
| Apr 19, 2021 at 10:21 | history | edited | Neeko | CC BY-SA 4.0 |
added 455 characters in body
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| Apr 16, 2021 at 11:08 | answer | added | devnull | timeline score: 2 | |
| Apr 16, 2021 at 10:49 | history | edited | JRE | CC BY-SA 4.0 |
added 10 characters in body
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| Apr 16, 2021 at 10:46 | answer | added | Bravale | timeline score: 0 | |
| Apr 16, 2021 at 9:42 | comment | added | Bimpelrekkie | Important note (maybe) my load is around 25mA. That is not a "maybe" the maximum load current can make or break this design. At 25 mA you're probably not going to dissipate that much heat in the components but do a calculation of that anyway! 36 V at 25 mA is 1 Watt so enough to fry a small component. Of course, some power goes into the load but consider where the rest will go. | |
| Apr 16, 2021 at 9:40 | comment | added | mmmm | Unless you're planning to draw only single, maybe two digits of milliamperes: almost certainly the approach of using a linear regulator here is a wrong way to start, unless you have plenty of heatsink to spare, anyway. | |
| Apr 16, 2021 at 9:38 | comment | added | Bimpelrekkie | Think about what happens when R9's value is too large: there will not be enough current through the zener (see zener's datasheet what (knee) current is needed). Also, if R9 is too large, Q1 might not have enough base current. You know the supply current so you can derive Ib from that. What if R9 has a value that is too low? Then too much current will flow through the zener, it will get hot. | |
| Apr 16, 2021 at 9:37 | history | edited | Transistor | CC BY-SA 4.0 |
Fixed spelling and capitalisation.
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| Apr 16, 2021 at 9:25 | history | edited | Neeko | CC BY-SA 4.0 |
added 148 characters in body
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| Apr 16, 2021 at 9:13 | history | asked | Neeko | CC BY-SA 4.0 |