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TimWescott
TimWescott
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You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel. When you connect two cells in parallel, the current going into or out of them splits. Assuming that the split is equal, then you get:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah (9.6 Wh) 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah (9.6 Wh) 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah (9.6 Wh) 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah (9.6 Wh) 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah (9.6 Wh) 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah (9.6 Wh) 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel. When you connect two cells in parallel, the current going into or out of them splits. Assuming that the split is equal, then you get:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah (9.6 Wh) 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah (9.6 Wh) 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah (9.6 Wh) 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

Added clarification of commonality between contended permutations.
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edit approved May 12, 2021 at 14:43
J Collins
edit approved May 12, 2021 at 14:43
J Collins
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You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah 1C(9.6 Wh) 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah 1C(9.6 Wh) 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah 1C(9.6 Wh) 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah (9.6 Wh) 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah (9.6 Wh) 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah (9.6 Wh) 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

corrected formatting of SI units
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Bruce Abbott
Bruce Abbott
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You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V V
    • 3V3 V 3.2A-h2 Ah 1C charge = 3.2A2 A. Split evenly over four cells, 3.2A2 A = 0.8A8 A/cell
  2. 2S 2P: 6 V V
    • 6V6 V 1.6A-h6 Ah 1C charge = 1.6A6 A. Split evenly over two strings of two cells 1.6A6 A = 0.8A8 A/cell
  3. 4S 1P: 12 V V
    • 12V12 V 0.8A-h8 Ah 1C charge = 0.8A8 A. There's just one string, so 0.8A8 A = 0.8A8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3V 3.2A-h 1C charge = 3.2A. Split evenly over four cells, 3.2A = 0.8A/cell
  2. 2S 2P: 6 V
    • 6V 1.6A-h 1C charge = 1.6A. Split evenly over two strings of two cells 1.6A = 0.8A/cell
  3. 4S 1P: 12 V
    • 12V 0.8A-h 1C charge = 0.8A. There's just one string, so 0.8A = 0.8A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

You are miscalculating, or neglecting to calculate, the effect on the capacity of the entire pack of connecting cells in parallel:

  1. 1S 4P: 3 V
    • 3 V 3.2 Ah 1C charge = 3.2 A. Split evenly over four cells, 3.2 A = 0.8 A/cell
  2. 2S 2P: 6 V
    • 6 V 1.6 Ah 1C charge = 1.6 A. Split evenly over two strings of two cells 1.6 A = 0.8 A/cell
  3. 4S 1P: 12 V
    • 12 V 0.8 Ah 1C charge = 0.8 A. There's just one string, so 0.8 A = 0.8 A/cell

(As a practical note, you can't trust that a parallel arrangement will split the current evenly -- just be aware).

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TimWescott
TimWescott
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