Timeline for Some LDO's specify noise in nV/Hz, others specify it in μV(rms). How do they equate?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 20, 2021 at 0:20 | vote | accept | KJ7LNW | ||
| May 19, 2021 at 12:00 | history | tweeted | twitter.com/StackElectronix/status/1394986199031365632 | ||
| May 19, 2021 at 11:37 | comment | added | user16324 | You are mixing up uV and nV : the TPS7a20 calculation should give you 22nV/rtHz. | |
| May 19, 2021 at 9:49 | history | became hot network question | |||
| May 19, 2021 at 4:02 | comment | added | user1850479 | Both of those datasheets give plots of the noise power vs frequency using identical units. Rather than look at the headline number (which depends on various factors and is anyway not likely to be the same bandwidth you care about), look at the noise plots. You'll see that (ignoring PSRR), the tps7a20 is much less noisy. | |
| May 19, 2021 at 3:50 | answer | added | V.V.T | timeline score: 5 | |
| May 19, 2021 at 2:35 | comment | added | Bruce Abbott | Thank you. Please correct your formula to match what the answer actually stated. | |
| May 19, 2021 at 2:29 | answer | added | filipmu | timeline score: 3 | |
| May 19, 2021 at 2:21 | comment | added | Bruce Abbott | "This SE answer compares the two mathematically as: (nV/√Hz) ⋅ √(bandwidth) = μVrms" - where does it state that? | |
| May 19, 2021 at 1:44 | history | asked | KJ7LNW | CC BY-SA 4.0 |