Timeline for How to turn 4 LEDs on one-by-one using a potentiometer (without programmable device)
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 17, 2021 at 12:36 | comment | added | WhatRoughBeast | You do need to rethink your requirements a bit. If the LEDs are off when the pot is at zero, and the bottom LED comes on when the pot is between 0 and 25%, exactly what level (greater than zero) turns on the LED? 2%,? 1%? 0.1%? This will make a difference in designing a practical circuit. If the answer is "any rotation of the pot", you're better off with a pot which contains a switch, so when you turn the pot away from the off position it allows power to the LED circuit. Portable radios (are they still a thing?) used this approach for a single knob which turns on/off and controls volume. | |
| Jun 17, 2021 at 11:22 | comment | added | john | Is there some reason why you wouldn't use a 4PST rotary switch? | |
| Jun 17, 2021 at 9:26 | answer | added | Neil_UK | timeline score: 1 | |
| Jun 16, 2021 at 20:51 | comment | added | glen_geek | If you're not too fussy about what LED ON means (regarding brightness), then a quad comparator isn't needed....a LED/resistor ladder should work. | |
| Jun 16, 2021 at 20:30 | history | edited | JRE | CC BY-SA 4.0 |
deleted 7 characters in body; edited title
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| Jun 16, 2021 at 20:29 | comment | added | ErikR | It'll work like this circuit does: hackaday.io/page/… | |
| Jun 16, 2021 at 20:21 | answer | added | D.A.S. | timeline score: 1 | |
| Jun 16, 2021 at 20:07 | review | First posts | |||
| Jun 17, 2021 at 2:04 | |||||
| Jun 16, 2021 at 20:06 | comment | added | uriyabsc | A simple voltage divider with a few window comparators should do the trick :) | |
| Jun 16, 2021 at 20:05 | comment | added | Neil_UK | quad comparator 339 | |
| Jun 16, 2021 at 19:58 | history | asked | Rom__ | CC BY-SA 4.0 |