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Jul 3, 2021 at 3:37 comment added rfdave Think about what a Smith chart represents. It's an impedance. Nothing more, nothing less. You could plot the impedance of a series RLC over frequency on a Smith chart, from one point to ground. Now, if you assume two ports (somewhere on that network) you can calculate a frequency response plot (Vout/Vin or Iout/In) showing gain and phase between those two points. However, those two points aren't represented on single smith chart, you need two (One for the input impedance, one for the output impedance) Now, consider active circuitry with gain and loss. How does that fit in a Smith chart?
Jul 3, 2021 at 3:28 comment added hotpaw2 Are you saying that there is zero relationship between complex impedance and frequency response in any circuit or system topology?
Jul 3, 2021 at 1:15 history answered rfdave CC BY-SA 4.0