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Jun 13, 2022 at 10:28 vote accept Brandon Kellett
Jul 15, 2021 at 16:12 comment added Kyle B This whole long-distance voltage drop thing is the reason there's a standard 4-20mA signal available for industrial controls.
Jul 15, 2021 at 14:42 answer added Neil_UK timeline score: 0
Jul 15, 2021 at 14:27 review Close votes
Jul 30, 2021 at 3:05
Jul 15, 2021 at 14:07 comment added rdtsc Does this answer your question? Avoiding DC voltage drop over long distances
Jul 15, 2021 at 12:14 comment added StainlessSteelRat Yes the distance has to be doubled. You have two wires.
Jul 15, 2021 at 11:52 comment added Bimpelrekkie ..the relations between voltage, current, power and resistance. Using 48 V and a couple of Ampere (so less than a few hundred Watt of power) you can practically span a distance of less than 10s of meters. I mean, 100 meter would already mean a lot of power loss. There is a reason why electricity is transported at for example 110 kV and higher: to keep currents low and thus keep the losses low.
Jul 15, 2021 at 11:51 comment added Bimpelrekkie What I am trying to essentially do is figure out what my limitations would be for sending 48V DC as far as possible You can send 48 V over practically any distance you like as long as there is no current flowing. But no current means no power (Power = voltage * current). "As far as possible" What does that mean? 48 V and a certain power means a certain current. That current in combination with the resistance of the wires and how much voltage drop you can accept will limit how long the wires can be. If you want to understand this better you need to study ...
Jul 15, 2021 at 11:48 answer added Justme timeline score: 2
Jul 15, 2021 at 11:23 history asked Brandon Kellett CC BY-SA 4.0