Timeline for Ideal v. Non-Ideal (?) Schmitt Trigger Transfer Curve
Current License: CC BY-SA 4.0
8 events
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| Sep 28, 2021 at 12:48 | comment | added | Simon Fitch | @VijayBharadwaj: Gain is about where the opamp wants the output to be, slew rate is about how quickly the output gets there. If the two are related, it's a very tenuous relationship. For instance, if the output is unable to reach where it's supposed to be quickly enough to follow the input, the output signal amplitude will be smaller than it should be, but it's not because of a problem with gain. | |
| Sep 28, 2021 at 11:58 | comment | added | Bimpelrekkie | What I meant was it tends to infinity IDEALLY. Does it not? No, "tends to infinity" doesn't mean much. What you could say is that you assume that the gain is infinite and that if that were true (and there are no other non-ideal effects, which there are), that you'd get the ideal curve. But you're still missing the point. Your sloped curves are not caused by the (lack of) gain. But by the fact that the opamp is too slow. | |
| Sep 28, 2021 at 11:50 | vote | accept | Vijay Bharadwaj | ||
| Sep 28, 2021 at 12:42 | |||||
| Sep 28, 2021 at 11:41 | comment | added | Vijay Bharadwaj | @Bimpelrekkie I get that it's not infinite. What I meant was it tends to infinity IDEALLY. Does it not? | |
| Sep 28, 2021 at 11:29 | comment | added | Bimpelrekkie | The gain is NEVER infinite. The gain is always limited. Do realize that at high gain (which applies here, you're using the opamp as a comparator) the opamp becomes SLOW. It will only change the output with a certain limited speed (slew rate). If you plot the output curve too fast, you will see that slope. | |
| Sep 28, 2021 at 11:20 | comment | added | Vijay Bharadwaj | Looking at Andy's answer above, do you mean that this slew rate leads to a non-infinite gain? | |
| Sep 28, 2021 at 11:09 | history | edited | Simon Fitch | CC BY-SA 4.0 |
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| Sep 28, 2021 at 11:02 | history | answered | Simon Fitch | CC BY-SA 4.0 |