Timeline for Find v(t) across the resistor in first order circuit
Current License: CC BY-SA 4.0
30 events
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| Aug 19, 2023 at 22:13 | answer | added | Jan Eerland | timeline score: 1 | |
| Aug 19, 2023 at 18:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 18, 2023 at 15:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 16, 2022 at 23:06 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 24, 2022 at 0:45 | answer | added | Fred Cailloux | timeline score: 0 | |
| Feb 21, 2022 at 13:47 | comment | added | Ani Lici | Let us continue this discussion in chat. | |
| Feb 21, 2022 at 13:46 | comment | added | Andy aka |
What does this mean: can we assume that the voltage across the capacitor and the resistance in series with the capacitor initially is 0? - does it mean is Vc = 0 AND is v(t) = 0 or does it mean that the combined voltage of Vc and v(t) (i.e. Vc + v(t)) = 0.
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| Feb 21, 2022 at 13:43 | comment | added | Ani Lici | @Andyaka what about now? Is it ok? | |
| Feb 21, 2022 at 13:42 | history | edited | Ani Lici | CC BY-SA 4.0 |
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| Feb 21, 2022 at 13:40 | comment | added | Andy aka |
And, with this new text: So all in all what I'm asking is :what is the voltage across the resistor R1 in series with the capacitor you are still being ambiguous. If you mean v(t) then say v(t) - don't try and be overly verbose on this because it isn't working. Then, you need to clarify if you want to know v(t) when t>0 or when t<0 or when t=0.
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| Feb 21, 2022 at 13:34 | comment | added | Andy aka |
This is hard work. You said this in your question: can we assume that the voltage across the capacitor and the resistance in series with the capacitor initially is 0? and I asked you to clarify what voltage you refer to. I then asked you to edit your question to make that bit unambiguous.
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| Feb 21, 2022 at 13:32 | comment | added | Ani Lici | @Andyaka ok just edited it | |
| Feb 21, 2022 at 13:31 | history | edited | Ani Lici | CC BY-SA 4.0 |
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| Feb 21, 2022 at 13:24 | comment | added | Andy aka | The original question so that it's clear what you are asking. | |
| Feb 21, 2022 at 11:15 | history | edited | Ani Lici | CC BY-SA 4.0 |
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| Feb 21, 2022 at 11:15 | comment | added | Ani Lici | @Andyaka what should i change? | |
| Feb 21, 2022 at 11:14 | comment | added | Andy aka | Please amend your question to express this because I don't particularly like answering questions that are drawn out in comments. | |
| Feb 21, 2022 at 11:13 | comment | added | Ani Lici | @Andyaka yes.exactly | |
| Feb 21, 2022 at 11:12 | comment | added | Andy aka | You mean v(t) then? | |
| Feb 21, 2022 at 11:12 | comment | added | Ani Lici | @Andyaka The resistor R1 | |
| Feb 21, 2022 at 11:12 | comment | added | Andy aka | No, I'm still confused as to what you mean. | |
| Feb 21, 2022 at 11:09 | comment | added | Ani Lici | @Andyaka oh im talking about the voltage across the resistor in series with the capacitor . the one in red in the photo | |
| Feb 21, 2022 at 10:54 | comment | added | Andy aka |
What is the voltage across the capacitor and resistance - be clearer is what I asked; I understand your justification and I understand there is only one capacitor but there are three resistors and also I'm unsure if you are talking about two voltages (across the capacitor AND across one of the resistors) OR you are talking about the voltage across the series combo of C and R1?
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| Feb 21, 2022 at 10:50 | comment | added | Ani Lici | @Andyaka Since the dependent voltage depends on the current ix but there is no voltage source to drive that ix i thought or assume that the current ix is 0. Therefore there is nothing running in the circuit and therefore the voltage across the capacitor and resistor is 0 | |
| Feb 21, 2022 at 10:48 | comment | added | Ani Lici | @Andyaka at t<0 when the switch is open. Since the capacitor is not charged in any way i thought that even though there is a dependent voltage source we dont have an actual voltage source for it to work. I dont know if i was clear but basically im asking. What is the voltage across the capacitor and resistance @t<0 | |
| Feb 21, 2022 at 10:27 | comment | added | Andy aka |
can we assume that the voltage across the capacitor and the resistance initially is 0? - be precise here.
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| Feb 21, 2022 at 1:58 | comment | added | Ani Lici | @FredCailloux im not sure if i understood your question but the ix i have there is just an indication where the dependent voltage source takes the ix from. And that is why im confused as well. The problem said "Find v(t) across the resistor". As i said in the question above if there is no initial source to "fill up " the capacitor can we assume that all the values are 0 in the begining? | |
| Feb 21, 2022 at 0:53 | comment | added | Fred Cailloux | I find your circuit confusing for initially ( when the switch is OPEN, no current ) there is this current generator that deliver 2ix current , yet further up there is an indication that the current is ix. Which makes no sense because the series C R1 have current to zero, because no current can circulate through a capacitor in a DC circuit. So initially , is there a 2ix current in the loop or is there a ix current in the loop ? | |
| Feb 20, 2022 at 21:33 | history | edited | winny | CC BY-SA 4.0 |
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| Feb 20, 2022 at 21:27 | history | asked | Ani Lici | CC BY-SA 4.0 |