Timeline for Can this resistor be replaced by a wire or fuse?
Current License: CC BY-SA 4.0
11 events
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S Apr 11, 2022 at 20:36 | history | suggested | Peter Mortensen | CC BY-SA 4.0 |
Copy edited (e.g. ref. <https://en.wikipedia.org/wiki/Ohm> and <https://en.wiktionary.org/wiki/reverse_engineering#Noun>).
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Apr 11, 2022 at 15:23 | review | Suggested edits | |||
S Apr 11, 2022 at 20:36 | |||||
Apr 11, 2022 at 9:19 | comment | added | MSalters | @seeker: What you will damage is at least the fuse. From P and R we can deduce V and I; about 12V and 1.2A. If you put in an 1.2A fuse, the remainder of the circuit would see a 12V higher voltage. Since the series resistance would now be lower by 15 Ohm, the current goes up and your 1.2A fuse melts. Hopefully it's the first thing to melt. | |
Apr 10, 2022 at 20:24 | comment | added | Mark | @seeker, no fuse has a correct rating. A fuse is simply a wire that's been engineered to melt under certain precise conditions. | |
Apr 10, 2022 at 16:29 | history | edited | Kuba hasn't forgotten Monica | CC BY-SA 4.0 |
added 149 characters in body
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Apr 10, 2022 at 9:38 | history | edited | Ralph | CC BY-SA 4.0 |
Unnecessary guessing work of the askers motivations. And he did accept this as the answer.
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Apr 10, 2022 at 6:19 | vote | accept | seeker | ||
Apr 10, 2022 at 6:19 | comment | added | seeker | Well now I get your point. I wanted to know likelihood I would damage anything by using e.g. fuse with correct rating. My bad since I wanted exact answer without providing schematics which is indeed not adequate . | |
Apr 10, 2022 at 6:15 | history | edited | SamGibson♦ | CC BY-SA 4.0 |
Added new information from now-deleted comment, that PSU provides expected output with resistor replaced by a fuse. Removed borderline unfriendly text - it is not up to us to tell someone not to ask a question.
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Apr 10, 2022 at 5:56 | history | edited | Kuba hasn't forgotten Monica | CC BY-SA 4.0 |
added 708 characters in body
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Apr 10, 2022 at 5:43 | history | answered | Kuba hasn't forgotten Monica | CC BY-SA 4.0 |