Timeline for Simplification down to a single resistor
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 12, 2022 at 13:48 | comment | added | Bertram | I see now. Thank you so much! | |
| Apr 12, 2022 at 13:23 | comment | added | Neil_UK | @Bertram Colouring in the nodes is mainly to help you make the redraw without error to get to my second diagram. From that it's clear that R1,4,5 are parallel, which are then in series with R2, which whole lot is now in parallel with R3. Just checked on a calculator and yes, that all comes to 3k, for the -60 V answer. I wouldn't try to figure out which resistors are series and parallel from the coloured schematic, I'm not clever enough, I'm sure I'd make a mistake. But from the redraw, it's obvious. | |
| Apr 12, 2022 at 13:20 | vote | accept | Bertram | ||
| Apr 12, 2022 at 13:12 | comment | added | Bertram | The 10k and 6k+12k+4k are in series, because the 10k is connected to the blue node? If the 10k resistor was connected to the red node (perhaps if there werent the 4k (V_0) resistor), it would be in series with the other three? | |
| Apr 12, 2022 at 8:44 | history | edited | Neil_UK | CC BY-SA 4.0 |
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| Apr 12, 2022 at 7:08 | history | edited | Neil_UK | CC BY-SA 4.0 |
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| Apr 12, 2022 at 4:59 | history | edited | Neil_UK | CC BY-SA 4.0 |
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| Apr 11, 2022 at 19:06 | history | answered | Neil_UK | CC BY-SA 4.0 |