Timeline for Why does MOSFET N back to back switch work?
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6 events
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May 1, 2022 at 9:24 | comment | added | Łukasz Przeniosło | Im not sure this is the same case. If we thread the transistor D-S patch as a resistor, then in the off state, we should have VIN at the sources. That is not the case. In off state, the potential measured at the sources is 0 V... | |
May 1, 2022 at 1:51 | comment | added | DKNguyen | @ŁukaszPrzeniosło If a circuit has a dead end resistor sticking out of it, and the end connected to the circuit measures 5V relative to GND, what's the voltage on open end of the resistor even though there is no current flowing through the resistor? electronics.stackexchange.com/questions/98322/… | |
Apr 30, 2022 at 5:57 | comment | added | Łukasz Przeniosło | But for any voltage to be present on the sources (0, lower or higher), there must be current flow from the M1 drain- is there any? | |
Apr 29, 2022 at 22:01 | comment | added | Lars Hankeln | @ŁukaszPrzeniosło With an initial "no voltage presence state" Vout will also be 0V and the Source node will be <0.7V. I wouldn't call that floating. | |
Apr 29, 2022 at 21:45 | comment | added | Łukasz Przeniosło | Thank you for answer. I still do not get it, and here I mean the very first turn on. Assume a no voltage presence state. The voltage is applied to VIN. GATE goes to a level VIN + 10 V, so the M1 can turn on- the thing I don't understand is: why does it turn on, if its source is not tied to any specific potential, but floating? | |
Apr 29, 2022 at 21:30 | history | answered | jp314 | CC BY-SA 4.0 |