Timeline for RC Timer Circuit (fundamental) Misunderstanding
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 15, 2022 at 18:00 | comment | added | Justin Thyme the Second | Show a grade ten student that circuit with C1 as a closed switch, and ask 'What will happen'? Then change C1 to an open switch, and ask 'What will happen?' Now task that student to imagine C1 as being a switch that slowly goes from closed to open, and ask 'What will happen?' No fancy equation with ridiculous exponents or doctorate thesis necessary. | |
| May 15, 2022 at 16:44 | comment | added | Elliot Alderson | You are confusing the behavior of one circuit, out of very many thousands of possible circuits, with the behavior of the capacitor itself. | |
| May 15, 2022 at 16:04 | comment | added | Justin Thyme the Second | @Elliot Alderson Absolutely true. Every charging curve for a capacitor demonstrated this. The RC time constant demonstrates this. As a capacitor charges, the current diminishes. As the capacitor charges, the voltage goes up. In a dc circuit such as the one given, the current though a capacitor (given a constant supply voltage) the current is inversely proportional to the voltage. Saying anything else is just wrong. That is how capacitors are used. | |
| May 15, 2022 at 13:01 | comment | added | Elliot Alderson | "The higher the voltage, the less current goes through it." Absolutely untrue. The current is proportional to the rate of change of voltage, it is not inversely proportional to the magnitude of the voltage. Ancient beliefs are not wrong just because they are ancient and facts are not beliefs. | |
| S May 15, 2022 at 3:47 | review | First answers | |||
| May 15, 2022 at 15:33 | |||||
| S May 15, 2022 at 3:47 | history | answered | Justin Thyme the Second | CC BY-SA 4.0 |