Timeline for Problem finding voltage in a circuit with mutual inductance
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 29, 2022 at 6:00 | history | tweeted | twitter.com/StackElectronix/status/1575364756269047808 | ||
| Sep 26, 2022 at 20:35 | history | edited | ocrdu | CC BY-SA 4.0 |
added 45 characters in body
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| Sep 26, 2022 at 17:40 | answer | added | Jan Eerland | timeline score: -1 | |
| Sep 24, 2022 at 0:52 | comment | added | jonk | @ricardovaras_99 I think so, too. I'm glad I may have helped somewhat. And thanks for letting me know your thoughts about this. Appreciated. | |
| Sep 23, 2022 at 21:28 | comment | added | ricardovaras_99 | @jonk thank you. I think that was the problem. | |
| Sep 23, 2022 at 21:23 | comment | added | ricardovaras_99 | @Andyaka just a misstype, the value was calculated with the sqrt. | |
| Sep 23, 2022 at 21:19 | history | edited | ricardovaras_99 | CC BY-SA 4.0 |
added 7 characters in body
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| Sep 23, 2022 at 8:05 | comment | added | Andy aka | Your formula for \$k\$ is incorrect. You forgot the square root. | |
| Sep 23, 2022 at 7:22 | comment | added | jonk | The current in L1 is 4 times the current in L2, so the magnitude of the current in L2 must be 4 times smaller. 10/4 = 2.5. Not so? So \$\frac{\text{d}}{\text{d} t}i_2=\frac14 \frac{\text{d}}{\text{d} t}i_1\$? | |
| Sep 23, 2022 at 2:28 | answer | added | Tesla23 | timeline score: 1 | |
| Sep 23, 2022 at 1:51 | history | asked | ricardovaras_99 | CC BY-SA 4.0 |