Timeline for How does capacitor C2 discharge?
Current License: CC BY-SA 4.0
15 events
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| Nov 2, 2022 at 18:37 | comment | added | G36 | Not AC? I think they show the "signal phase". And this picture is showing the charging phase drive.google.com/file/d/12wOoLKGbYp1PKxAut9bOVpINPLnKZr-K/view | |
| Nov 2, 2022 at 8:25 | comment | added | Heroz | @G36........... Wave form in picture it's not AC right? | |
| Nov 1, 2022 at 15:48 | comment | added | Heroz | Sorry in this picture drive.google.com/file/d/12wOoLKGbYp1PKxAut9bOVpINPLnKZr-K/… it charged at positive side and when it will discharge follow this path right? | |
| Nov 1, 2022 at 15:10 | comment | added | G36 | @Heroz Yes, it will follow this path during charging phase. | |
| Nov 1, 2022 at 14:38 | comment | added | Heroz | So if it charge as picture drive.google.com/file/d/12wOoLKGbYp1PKxAut9bOVpINPLnKZr-K/… , It will follow this path right? | |
| Nov 1, 2022 at 13:26 | comment | added | G36 | Play with this tinyurl.com/2y8gpu6g | |
| Nov 1, 2022 at 12:15 | comment | added | Heroz | @DaveTweed..... Thank you very much . So it discharge through R5>>ground>>9V>>R3>>R1>> and the other side of the capacitor path. | |
| Nov 1, 2022 at 11:30 | comment | added | Dave Tweed | As it does so, the negative voltage at the base of "NPN (TOT)" rises, and once it becomes positive by enough to turn the transistor on, the cycle repeats. This is a form of "relaxation oscillator". Don't be confused by the little sine wave notations in the schematic -- the actual waveform is quite different. | |
| Nov 1, 2022 at 11:26 | comment | added | Dave Tweed | Yes. Once C2 approaches full charge, the current through it drops low enough that "NPN (TOT)" cuts off. This causes T1 to cut off as well, and R5 pulls the positive end of C2 to ground. This means that the other end of C2 becomes negative with respect to ground, reinforcing the fact that both transistors are off. Now the only path for current is through R3 and R1 -- arrow (2). Since this current is the reverse of the charging current, C2 now discharges -- relatively slowly, since R1 is so large relative to R3 and R5. | |
| Nov 1, 2022 at 11:22 | history | edited | winny | CC BY-SA 4.0 |
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| Nov 1, 2022 at 11:08 | comment | added | Heroz | Does capacitor C2 discharge ? In this circuit C2 is non polarized capacitor I add positive sign to show that now it charged this side . | |
| Nov 1, 2022 at 11:07 | comment | added | Dave Tweed | See the arrow labelled (1)? The BE junction is forward biased, so it doesn't block the current. T1 is the source of that current. The reverse current is shown by arrow (2), which follows the path you described. R3 is the source of that current. | |
| Nov 1, 2022 at 10:09 | history | edited | Heroz | CC BY-SA 4.0 |
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| Nov 1, 2022 at 10:01 | history | edited | ocrdu | CC BY-SA 4.0 |
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| Nov 1, 2022 at 9:58 | history | asked | Heroz | CC BY-SA 4.0 |