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Nov 16, 2022 at 22:20 comment added Kartman If in doubt, there are simulators that you can use to validate your calcs. Online sims like falstad make the barrier of entry low. The sims can be a little quirky, so expect to spend a little time to understand how to work them. Don’t fall into the trap of having the simulator replacing the theory you are learning!
Nov 16, 2022 at 19:45 history edited ocrdu CC BY-SA 4.0
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Nov 16, 2022 at 19:19 answer added jonk timeline score: 2
Nov 16, 2022 at 18:55 comment added jonk All you have to do is to create the simple triangles for each of the other two branches. Both have a resistance, which goes onto the positive-going x-axis direction. One branch has an inductance which traditionally goes on the positive-going y-axis, while the other branch has a capacitance which traditionally goes on the negative-going y-axis. These are two completely independent triangles, computed separately from each other. You can get the hypotenuse (magnitude) and the angle and its sign.
Nov 16, 2022 at 18:02 comment added jonk The resistance of the first branch is, in fact, \$20\:\Omega\$. You got that right. However, the moment you start worrying about the \$20\:\Omega\$ with other components is where you go off the rails. The \$20\:\Omega\$ is directly across an ideal voltage source, so it has NO impact on the branch currents in the rest of the circuit. It is independent. You will need it if you want to compute the ideal AC source current. But not to calculate the other branch currents. In fact, all three branches are independent from each other as they are all directly connected to an ideal voltage source.
S Nov 16, 2022 at 17:55 review First questions
Nov 16, 2022 at 19:45
S Nov 16, 2022 at 17:55 history asked NonComposMentis CC BY-SA 4.0