Timeline for Finding Vrms over time
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 8, 2022 at 11:12 | comment | added | user97662 | Looks like my 'book' answer for the 3rd term is also incorrect, it somehow got to the right answer due to the symmetric property of the waveform. The correct way to write the 3rd term if one were to evaluate from 0 to \$\frac{5T}{15}\$ should be: \$\frac{1}{T}\int_{0}^{5T/15}(\frac{-V_{max}\cdot15}{5T})^2\cdot(t-5T/15)^2\$ | |
| Dec 8, 2022 at 11:00 | comment | added | jdum | There are two known points for the function: \$f(t=T)=0\$ and \$f(t=\frac{10T}{T})=V_{max}\$. Solve for the unknowns in the target function \$f(t) = a(t-b)\$ and you will find the answer. | |
| Dec 8, 2022 at 10:56 | history | edited | jdum | CC BY-SA 4.0 |
error fixed
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| Dec 8, 2022 at 10:50 | comment | added | user97662 | I tried it, and it works, but where does the -T come from? Is it because it did not start at T=0? How come it is not -10, since it starts at t=10msec? | |
| Dec 8, 2022 at 10:43 | vote | accept | user97662 | ||
| Dec 8, 2022 at 15:36 | |||||
| Dec 8, 2022 at 10:39 | history | edited | jdum | CC BY-SA 4.0 |
added integral to equation
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| S Dec 8, 2022 at 10:31 | review | First answers | |||
| Dec 8, 2022 at 11:14 | |||||
| S Dec 8, 2022 at 10:31 | history | answered | jdum | CC BY-SA 4.0 |