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Jan 6, 2023 at 2:50 answer added Tim Williams timeline score: 4
Jan 5, 2023 at 18:00 history tweeted twitter.com/StackElectronix/status/1611059959982071809
Jan 5, 2023 at 16:24 history became hot network question
Jan 5, 2023 at 15:46 answer added LorenzoDonati4Ukraine-OnStrike timeline score: 4
Jan 5, 2023 at 15:43 vote accept tobalt
Jan 5, 2023 at 14:38 history edited winny CC BY-SA 4.0
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Jan 5, 2023 at 14:33 answer added John Birckhead timeline score: 15
Jan 5, 2023 at 14:20 answer added Ken Grimes timeline score: 9
Jan 5, 2023 at 12:36 comment added Andy aka That video is inapplicable as far as I can tell. The eddy current losses in the vitroperm take power from the source but, do not stop the magnetic field being coupled to the secondary. Look at the equivalent circuit for a transformer; if leakage losses are small (as you would expect with a transformer) providing the source can still apply the same voltage, the coupling of that voltage to the output via the turns ratio is unaffected.
Jan 5, 2023 at 12:11 comment added tobalt @Andyaka I always have that mental picture in my head that Todd Hubing nicely demoes here: youtube.com/watch?v=_Zq6qiuuINE&t=375s The conductive shield inserted between a sender and receiver coil, generates an opposing magnetic field (eddy currents) reducing the coupling very severly - the essence of shielding. Could you maybe add a thought of why this might be different (or less important) in a transformer ?
Jan 5, 2023 at 11:34 comment added Andy aka Eddy current losses don't stop it operating as a transformer. I've used pieces of ferrite at hundreds of MHz to improve coupling of signals from one coil to another coil and ferrite losses at hundreds of MHz are just as bad (if not worse) than vitroperm at your frequency range.
Jan 5, 2023 at 10:38 history edited tobalt CC BY-SA 4.0
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Jan 5, 2023 at 10:35 comment added tobalt @Andyaka well I am not looking for a quantitative "solution" for R2/R3. I am just puzzled, why this transformer works at all at frequencies, well beyond where its core material becomes profoundly dissipative. A lower R2/R3 would be just a schematic concept that would express such lossiness. I will reformulate that section.
Jan 5, 2023 at 10:30 comment added Andy aka I don't see how anyone can answer about the values of R2 and R3 with the information you have presented.
Jan 5, 2023 at 8:18 history asked tobalt CC BY-SA 4.0