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Andy aka
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It says the maximum current is 35 mA and, that would mean the transistor might be on-the-cusp of failing so, choose a more reasonable current like 5 mA and calculate a resistor value that's 1 kΩ. You could probably go as low as 1 mA with a 5 kΩ resistor.

But, there is a minor problem pointed out by @periblepsis; the minimum supply voltage for this device is 12 volts so, in effect, you'll have to use two resistors and form a potential divider like this: -

enter image description here

It says the maximum current is 35 mA and, that would mean the transistor might be on-the-cusp of failing so, choose a more reasonable current like 5 mA and calculate a resistor value that's 1 kΩ. You could probably go as low as 1 mA with a 5 kΩ resistor.

It says the maximum current is 35 mA and, that would mean the transistor might be on-the-cusp of failing so, choose a more reasonable current like 5 mA and calculate a resistor value that's 1 kΩ. You could probably go as low as 1 mA with a 5 kΩ resistor.

But, there is a minor problem pointed out by @periblepsis; the minimum supply voltage for this device is 12 volts so, in effect, you'll have to use two resistors and form a potential divider like this: -

enter image description here

Source Link
Andy aka
  • 473.1k
  • 29
  • 383
  • 839

It says the maximum current is 35 mA and, that would mean the transistor might be on-the-cusp of failing so, choose a more reasonable current like 5 mA and calculate a resistor value that's 1 kΩ. You could probably go as low as 1 mA with a 5 kΩ resistor.