What are the effects of the pull-down resistor (33K) when the solenoid-valve enters its turn-off phase?
It is in parallel with the coil, so will serve to discharge the current in the coil.
Will it prevent the solenoid-valve from ever discharging because current would flow from ground through the pull-down resistor to the solenoid-valve?
No, it will help discharge the solenoid in a more controlled manner.
Without it, the solenoid will discharge even faster, but produce a much higher reverse peak voltage when shut off.
With a lower value such as 1k, the solenoid will discharge slower, but produce a much smaller reverse peak voltage when shut off.
How do we protect the MOSFET (e.g. clamping) when the solenoid is in the turn-off phase?
If speed is not an issue, then a garden-variety 1N400x diode is used instead of a resistor. This makes the coil open very slowly, but blocks the peak reverse spike to -0.7V or so.
If Ids Max is 2A and the solenoid IPeak was 25mA (derived from 0.35W solenoid spec), should I even be concerned about protecting the MOSFET during the turn-off phase?
Absolutely. The inductance is stated as 323.2 Henries, which is a lotfair amount of inductance. Such an inductor could make spikes in the tens of kilovolts range. Without some means to clamp that spike, it will destroy the MOSFET.