Timeline for Equipment to throttle energy consumption of 220V AC device (Solar+grid)
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
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Jul 27, 2023 at 3:01 | comment | added | vu2nan | The resistance of a water heater does not drastically increase with temperature. The temperature coefficient of resistance of Nichrome is only 0.00017 per ° C and of Nichrome V only 0.00013 per ° C. | |
Jul 26, 2023 at 19:36 | comment | added | Marcus Müller | ah, I get it. But honestly, a boiler's hot water reservoir would be a much easier storage of energy, compared to a flywheel. Simply only heat more water when there's an excess of power! | |
Jul 26, 2023 at 19:31 | comment | added | Criticizing Israel not allowed | @MarcusMüller If you just turn the water heater on and off, you'll be drawing from the power grid when it's on, and exporting to the power grid when it's off, so you put something in the way to smooth that out. As I said, silly idea, not practical. | |
Jul 26, 2023 at 17:29 | comment | added | Marcus Müller | why the "motor->flywheel->generator" detour in that, @user253751? What's the idea there? | |
Jul 26, 2023 at 17:02 | comment | added | Criticizing Israel not allowed | I won't make it an answer because it's not practical, but motor->flywheel->generator->PWM switch->water heater | |
Jul 26, 2023 at 14:34 | comment | added | Marcus Müller | That's the thing: when cold, the thing has lower resistance, so if you calculate your transformer for 400W, you might quickly be saturating the transformer core, because the heater never gets hot. | |
Jul 26, 2023 at 14:33 | comment | added | Julien | He wouldn't need a 2kW transformer! Only 400W ish. Even if resistance varies, power on water heater are not that accurate. It wouldn't make any significant difference. | |
Jul 26, 2023 at 14:28 | comment | added | Marcus Müller | A 2 kW transformer would sound like an expensive solution, but yeah, should work. Don't forget that the resistance of a heater probably drastically increases with temperature – so, you need to take that into account in your R=V²/P calculation. A cold heater will draw more current than a hot one! | |
Jul 26, 2023 at 14:26 | history | answered | Julien | CC BY-SA 4.0 |