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Oct 10, 2023 at 18:30 comment added Cristobol Polychronopolis @DevelopingElectronics I understand, but you can eliminate the two P-channel FETs going to Vdd without affecting the operation of the circuit; the other side of the load is already connected to Vdd. Option (a) is your correct connection, as (b) will never pass current (except in short bursts during switching). You can see why the P-channels aren't needed.
Oct 4, 2023 at 6:27 comment added Developing Electronics @CristobolPolychronopolis I have two logic inputs, that's why a single MOSFET does not work for me.
Sep 28, 2023 at 20:54 comment added Cristobol Polychronopolis You could probably just use the N-channel FET(s) instead of implementing the entire gate.
Sep 28, 2023 at 20:06 answer added Kuba hasn't forgotten Monica timeline score: 1
Sep 28, 2023 at 17:29 history reopened Davide Andrea
Voltage Spike
S Sep 28, 2023 at 11:52 review Reopen votes
Sep 28, 2023 at 17:29
S Sep 28, 2023 at 11:52 history edited Developing Electronics CC BY-SA 4.0
added 60 characters in body Added to review
Sep 26, 2023 at 11:33 history closed Tim Williams
ocrdu
Jens
Needs details or clarity
Sep 26, 2023 at 9:55 review Close votes
Sep 26, 2023 at 11:33
Sep 26, 2023 at 8:45 comment added Developing Electronics It is not in the pictures. Its one commercial driver I used to drive the Mosfets' gates with PWMs. I know there are some of them with an enable pin, but I need another extra enabling, like I said before.
Sep 26, 2023 at 8:40 comment added Tim Williams What H-bridge driver?
Sep 26, 2023 at 8:38 comment added Developing Electronics The gates of the h brisge MOSFETs are control from an h bridge driver that will drive the PWM. I can't do that. I need a solution similar to the one I am asking for.
Sep 26, 2023 at 8:21 comment added Tim Williams You connect the logic device to the logic inputs of the H-bridge. Not the power pins.
Sep 26, 2023 at 8:14 history asked Developing Electronics CC BY-SA 4.0