Timeline for Can an entire signal with transients be reconstructed from an inverse Fourier transform?
Current License: CC BY-SA 4.0
19 events
| when toggle format | what | by | license | comment | |
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| Oct 29, 2023 at 14:11 | vote | accept | thepman | ||
| Oct 28, 2023 at 23:09 | comment | added | Luca Citi | @TimWilliams "and complex valued" yes but with pairs of complex conjugate points (e.g. positive and negative frequencies) so overall the exact same number of bits (no doubling due to being complex) | |
| Oct 28, 2023 at 22:50 | comment | added | thepman | I'm asking more conceptually.. So if it was done on a computer with infinite power and RAM etc what it would look like, so it could be infinite. | |
| Oct 28, 2023 at 22:13 | history | became hot network question | |||
| Oct 28, 2023 at 19:35 | answer | added | Math Keeps Me Busy | timeline score: 1 | |
| Oct 28, 2023 at 17:40 | comment | added | Tim Williams | Trivially yes. But keep in mind what you're proposing. For a sampled windowed input (as digital audio), the output will be the DFT, with as many bins as there were samples in the input, and complex-valued. Is this what you were asking, or were you thinking of other formats? | |
| Oct 28, 2023 at 17:39 | answer | added | user107063 | timeline score: 4 | |
| Oct 28, 2023 at 17:11 | history | edited | JRE | CC BY-SA 4.0 |
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| Oct 28, 2023 at 14:39 | comment | added | user1850479 | The Fourier transform is integral from - to + infinity, so as long as your signal is shorter than infinity, the "change" is within the integral and thus encoded in the magnitude/phase. For transfinite signals the integral diverges and you don't get a transform. | |
| Oct 28, 2023 at 14:24 | answer | added | Dave Tweed | timeline score: 5 | |
| Oct 28, 2023 at 14:15 | history | edited | thepman | CC BY-SA 4.0 |
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| Oct 28, 2023 at 14:01 | answer | added | Julien | timeline score: -3 | |
| Oct 28, 2023 at 14:00 | comment | added | thepman | Sorry, I meant if you also have phase. So for each frequency you know it's magnitude and phase. But these are properties that might change over time in the original signal. | |
| Oct 28, 2023 at 13:54 | comment | added | user1850479 | If you only have magnitude then that is not a Fourier transform but a power spectrum. The Fourier transform is invertible but power spectrum is not. You need the complex value to figure out where transients happen in time and so it's not invertible if you don't have phase. | |
| Oct 28, 2023 at 13:47 | history | edited | JRE | CC BY-SA 4.0 |
deleted 11 characters in body; edited title
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| S Oct 28, 2023 at 13:43 | history | suggested | Ergophobia | CC BY-SA 4.0 |
fixed grammer,improved formating
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| Oct 28, 2023 at 12:56 | review | Suggested edits | |||
| S Oct 28, 2023 at 13:43 | |||||
| S Oct 28, 2023 at 12:43 | review | First questions | |||
| Oct 28, 2023 at 12:45 | |||||
| S Oct 28, 2023 at 12:43 | history | asked | thepman | CC BY-SA 4.0 |